Paper 2026/2411

Average-Case Hardness of Lattice Problems in Special Genera of Fixed Rank

Abstract

The distinguishing variant $\Delta$LIP of the Lattice Isomorphism Problem underlies the security proofs of a growing family of lattice-based schemes. As the special genus is the strongest efficiently computable invariant of a lattice, such a proof may replace the lattice used by the scheme with a random lattice of the same genus. This raises the question of how hard lattice problems actually are on such random lattices. We answer it, under GRH, with a worst-case to average-case reduction inside any special genus $\mathcal{G}$ of Hermitian lattices of fixed rank $r \geq 2$ over a cyclotomic field $K$ of degree $d$: for each of $\mathrm{(H)SVP}$, $\mathrm{HCVP}$, $(\Delta)\mathrm{BDD}$, $\mathrm{DSP}$ and $\mathrm{DGS}$, solving the problem on a random class of $\mathcal{G}$, drawn from its natural distribution, is as hard as solving it on the worst-case lattice of $\mathcal{G}$, at the cost of a factor $p = \mathrm{poly}(d) \cdot {\det}_{\mathbb{Q}}(\Lambda)^{O_r(1)/d}$ in the approximation factor. The reduction is a random walk on the Kneser $\mathfrak{p}$-neighbour graph of $\mathcal{G}$: neighbours stay close enough to transfer problem instances, while the walk equidistributes quickly, a fact we deduce from spectral bounds for the associated Hecke operators. As an application we give a direct and tight security proof for a minimal LIP-based KEM, resting on two independent assumptions: that the lattice it uses is indistinguishable from a random lattice of its genus, and that $\Delta$BDD is hard on that genus. Unlike existing LIP-based proofs, this requires neither an ad-hoc lattice of the form $q\Lambda \oplus (q+1)\Lambda$, nor the tightness loss caused by the dense sublattice such proofs rely on.