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2012/022 - Section 5.1
Posted by: hadimc (IP Logged)
Date: 13 June 2012 06:31

Hello,

Page 10: Is this correct H_\infty(R|Z) = n lg (1/(1-p_A))?

It definitely is the case when no coding is used. But generally R includes 'k<n' random bits and hence H-\infty(R|Z) \leq k lg (1/(1 - p_A)) should hold. The code redundancy will decrease this even more... Am I missing something?

Thanks,
Hadi Ahmadi



Edited 1 time(s). Last edit at 13-Jun-2012 16:31 by hadimc.



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